Philly’s Robinson to defend NABO title; set to take on Alimjanov

BY: Richard Quiñones (Journeymen Boxing) JMB has learned that Philadelphia welterweight the “New” Ray Robinson will defend his NABO welterweight title against Sherzodbek Alimjanov in a slated 10-round affair, which was added to the Roc Nation Sports card to be held Friday April 17th at Foxwoods Resort in Mashantucket, Connecticut.

The talented southpaw Robinson (19-2, 9ko’s) has been climbing up the ranks and has had several very impressive performances over the last year. He easily defeated and outclassed Daniel Sostre last November to earn the vacant WBO NABO welterweight title.

“I have been working really hard,” said Robinson exclusively to JMB Monday night. “I want to make sure the NABO belt stays in Philly.”

He is ranked 7th in the WBO and 8th in the WBC.

The 5’10 Robinson is a slick boxer, who has really made others in a stacked welterweight division take notice of him, especially when he dominated a then undefeated Aslanbek Kozaev. The smaller Russian looked confused all night long en route to dropping an unanimous decision.

Alimjanov (22-2, 13ko’s) has won two straight since losing a 12-round unanimous decision against Dmitry Mikhaylenko for the vacant WBO European welterweight title back in 2012. He took two years off before returning to the ring in 2014, when scored a third-round KO win over Jaba Shalutashvili.

“I really do not know that much bout him (Alimjanov), he is right-handed but likes to switch here and there,” Robinson concluded.





Posted by RQ

This article has 2 Comments

  1. Is Ray still with TNT Tiberi, I heard the kid is getting a bit to cocky and wants the money fights, he needs to pay hu dues more. Slick southpaw, but needs to be tested

  2. Bruce, do you even follow boxing. Ray fought Porter and Solomon, destroyed that Russian kid and I heard they even put a call into fight that kid down in DC, Hernandez, who wanted know part of him. So please stop with the stuff that he needs to be tested, dude is ranked in top 10.

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